Calendar
Quantitative Aptitude · Numbers & Mensuration · 3 min
Concept: Calendar — counting odd days
The whole topic runs on one idea: an odd day is the remainder left after taking out complete weeks.
- An ordinary year has 365 days = 52 weeks + 1 odd day.
- A leap year has 366 days = 52 weeks + 2 odd days.
- 100 years give 5 odd days, 200 give 3, 300 give 1, and 400 give 0.
Leap year test: divisible by 4 — except a century year, which must be divisible by 400. So 2000 was a leap year, but 1900 and 2100 are not. That exception is the single most common mistake in this topic; candidates count 1900 as a leap year and land one day off.
Three question types:
- What day was date X? Count the odd days between a date you know and date X, then move that many weekdays forward.
- Which date is the nth day of a year? Add the month lengths (31, 28 or 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31) until you pass n.
- Which year repeats this calendar? The odd days accumulated in between must total a multiple of 7, and both years must be of the same kind (ordinary or leap).
Counting rule for type 1: when the span from one date to the same date next year includes a 29 February, it is 366 days, so the weekday advances by 2, not 1.
Formula card
ordinary year 1 odd day · leap year 2 · 100 yr 5, 200 yr 3, 300 yr 1, 400 yr 0 · leap = ÷4, century must be ÷400 · odd days 0 = Sunday … 6 = Saturday
Worked example
15 August 1947 was a Friday. What day was 15 August 1948? → The span is one year that contains 29 February 1948, so it is 366 days = 52 weeks + 2 odd days. Friday + 2 = Sunday. Sanity check: had 1948 not been a leap year the span would have been 365 days and the answer Saturday — the leap day is worth exactly one extra weekday.